Submission #187756

---

Source Code Expand

N = gets.chomp.to_i
a = []
3.times do
  a.push(gets.chomp.to_i)
end
a.sort!.reverse!

n = N
c = 100
until c <= 0
  if n != 0
    while a[0] and a[0] >= n
      a.shift
    end
    if !a.include?(n-3)
      n -= 3
    elsif !a.include?(n-2)
      n -= 2
    elsif !a.include?(n-1)
      n -= 1
    else
      puts 'NO'
      exit
    end
  end
  c -= 1
end

puts(if n <= 0
    'YES'
  else
    'NO'
  end)

Submission Info

Judge Result